Posted by **Amber** on Sunday, February 3, 2013 at 12:29am.

I need help please!!!

On January 1, 2010, Chessville has a population of 50,000 people. Chessville then enters a period of population growth. Its population increases 7% each year. On the same day, Checkersville had a population of 70,000 people. Checkersville starts to experience a population decline. Its population decreases 4% each year. During what year will the population of Chessville first exceed that a Checkersville? Show all of your work and explain your steps.

Any help would be great.

- Alegebra I -
**Henry**, Monday, February 4, 2013 at 7:32pm
50000 + 0.07x*50000>70000-0.04x*70000.

50000 + 3500x > 70000 - 2800x

3500x + 2800x > 70000 - 50000

6300x > 20000

X > 3.17 yr.

So the population of Chessville becomes greater than the population of Checkers-

ville during the 3rd yr.

- Alegebra I -
**Henry**, Monday, February 4, 2013 at 7:55pm
Correction: Change > to =.

X = 3.17460 Years.

## Answer This Question

## Related Questions

- Algebra - On Jan 1, 2010, Chessville has a population of 50,000 people. ...
- Algebra - On Jan 1, 2010, Chessville has a population of 50,000 people. ...
- Algebra - On Jan 1, 2010, Chessville has a population of 50,000 people. ...
- Algebra - On Jan 1, 2010, Chessville has a population of 50,000 people. ...
- Math - I know that year 2010, the population is 38.447 million and year 2011, ...
- Algebra 1 - The population of a city increases by 4,000 people each year. In ...
- Math - The population of a city increases by 4,000 people each year. In 2025, ...
- College Algebra - Find a linear equation in the form P = mt + b (y = mx + b), ...
- Math - According to the U.S Bureau of Census in the year 1850 the population of...
- algebra - Find a linear equation in the form P = mt + b (y = mx + b), which ...

More Related Questions