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December 21, 2014

December 21, 2014

Posted by **Amy** on Sunday, February 3, 2013 at 12:23am.

What I need help with is how to set up the equation. I have the Ea, which is 41.4 degrees C, and the activation energy, which is 32.9 kJ/mol.

- How to Set Up Equation -
**DrBob222**, Sunday, February 3, 2013 at 12:31amYou have a typo in your post. I don't know what Ea is, either 32.9 or 41.4.

From the data you have and from what I remember about earlier posts I think it is this.

k1 = not given but refers to problem x @ 298.15

k2 = ? @ 403.15

ln(k2/k1) = (Ea/R)(1/298.15 - 1/403.15) and you want to solve for k2.

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