Given that the initial rate constant is at an initial temperature of 25 degrees C, what would the rate constant be at a temperature of 130 degrees C for the same reaction described in Part A?
What I need help with is how to set up the equation. I have the Ea, which is 41.4 degrees C, and the activation energy, which is 32.9 kJ/mol.
How to Set Up Equation - DrBob222, Sunday, February 3, 2013 at 12:31am
You have a typo in your post. I don't know what Ea is, either 32.9 or 41.4.
From the data you have and from what I remember about earlier posts I think it is this.
k1 = not given but refers to problem x @ 298.15
k2 = ? @ 403.15
ln(k2/k1) = (Ea/R)(1/298.15 - 1/403.15) and you want to solve for k2.