how many grams of magnesium are required to react with 2.0 moles of hydrochloric acid?
2 moles of HCl *(36.5 g of HCl/mol)=moles of HCl
Since moles of HCl=moles of Magnesium,
moles of Mg*(24.3g og Mg/mol)= g go Mg
Mg + 2HCl ==> MgCl2 + H2
2 mols Mg x (2 mols HCl/1 mol Mg) = 4 mols HCl.
g HCl = 4 mols HCl x molar mass HCl. = 4*36.5 = ?
Opps,
2 moles of HCl *(36.5 g of HCl/mol)=moles of HCl
Since 2 moles of HCl=moles of Magnesium,
moles of HCl *(1 mole of Magnesium/2 moles of HCl)*(24.3g og Mg/mol)= g go Mg
I apologize
Isn't it two moles of HCl for one mole of Mg?
I screwed up. I completely read the problem wrong. The equation I wrote is correct which, I suppose, led to Devron correcting his response. I gave you the answer for mols HCl for 2 mol Mg and that wasn't the question. Sorry about that.
I was correcting it, and didn't know that you were correcting it. i went back and looked at what I did, and after looking at the question again, I noticed that I assumed it was a 1:1 mole reaction, isn't the case. When I refreshed the window, because sometimes you and the poster post a response while I type slowly, I noticed what you did and asked the question.
To determine the grams of magnesium required to react with 2.0 moles of hydrochloric acid, we need to calculate the molar ratio between magnesium and hydrochloric acid and apply it to the given number of moles of hydrochloric acid.
The balanced chemical equation for the reaction between magnesium (Mg) and hydrochloric acid (HCl) is:
Mg + 2HCl -> MgCl2 + H2
From the equation, we can see that 1 mole of magnesium reacts with 2 moles of hydrochloric acid.
Now, we'll use the molar ratio to find the moles of magnesium that would react with 2.0 moles of hydrochloric acid:
1 mole of Mg corresponds to 2 moles of HCl.
Thus, 2.0 moles of HCl correspond to (2.0 moles HCl) / (2 moles HCl/Mg) = 1.0 mole of Mg.
Finally, we can determine the grams of magnesium required by multiplying the number of moles of magnesium by its molar mass. The molar mass of magnesium is approximately 24.31 grams/mole.
Grams of Mg = (1.0 mole Mg) x (24.31 grams/mole Mg) = 24.31 grams of magnesium.
Therefore, 24.31 grams of magnesium are required to react with 2.0 moles of hydrochloric acid.