Posted by Lisa on Saturday, February 2, 2013 at 7:43pm.
mass=density(volume)=density*area*length
where area=sqrt(s(s-a)^3) s=half perimeter=(3in*2.54cm/in)*3/2
area=sqrt(9*1.27(3*2.54*2))
check that.
thank you
How many inches is the section of the bar
I'm not sure that I understand what you did, but this is what I did.
1kg=1 x10^3 g
Density=Mass/volume, so
Volume =mass/density= (1 x10^3 g/7.70g/cm^3)= 130cm^3
Since in a equilateral triangle all sides are equal and since volume = cm*cm*cm or l*w*h
(130cm^3)^(1/3)=5.06cm
Converting to inches
5.06cm*(1in/2.54)= 2 inches/side
Related Questions
Maths - A steel bar 3.6m long is in the form of a triangular prism.its section ...
CHEM - Factors which effect reaction rates. 1) Concentration 2) Temperature 3) ...
mechanics of materials - A steel bar with a cross sectional area of 25cm2 is ...
mechanics of materials - A steel bar with a cross sectional area of 25cm2 is ...
Physics - a standard man wants to do reverse curls in a gym. He holds his arms ...
Physics - A standard man wants to do reverse curls in a gym. He holds his arms ...
Physics - a standard man intending to do reverse curls in a gym. He holds his ...
Kinematics. Newtons Laws - A standard man does reverse curls in a gym. He holds ...
Physics - a standard man intending to do reverse curls in a gym. He holds his ...
physics - A light rigid bar is suspended horizontally from two vertical wires, ...
For Further Reading
