Posted by **Anonymous** on Saturday, February 2, 2013 at 7:33pm.

How many grams of K2Cr2O7 are required to prepare 500 ml of a 0.13 N solution?

- Analytical chemisty -
**Devron**, Saturday, February 2, 2013 at 10:51pm
0.13N= # of equivalents/500 x10^-3 L, solving for # of equivalents

# of equivalents in 0.13N=(0.13N)(500 x 10^-3L)

# of equivalents in 0.13N= g of solute/49.03g, solve for grams of solute,

(49.03g, solve )*(# of equivalents in 0.13N)= g of solute

## Answer This Question

## Related Questions

- analytical chemisty - Consider the standardization of a solution of K2Cr2O7 with...
- Analytical chemistry - How many grams of solid CuSO4. 5H2O are needed to prepare...
- chemistry - the amount of K2Cr2O7 required to prepare 100ml of its 0.05N ...
- Chemistry - Need help with problem (Molarity) How many grams of NaOH are ...
- Analytical Chemistry - calthe culate mass of 10% stock solution required to ...
- Analytical chemistry - an 0.5031 gram sample of iron ore is determined through ...
- Chemisty - A 2.5 L volume of sodium hydroxide solution was prepared. The titrant...
- chemistry - How many grams of sodium hydroxide are required to prepare 500 mL of...
- Analytical Chemistry - A 10.0 mL sample of whiskey was diluted to 500.0 mL. A 4....
- chemisty - how many grams of magnesium sulfate are required to make 575 ml of a ...

More Related Questions