Posted by **Wes** on Saturday, February 2, 2013 at 6:46pm.

Wes and Lindsay stand on the roof of a building. Wes leans over the edge and drops an apple. Lindsay waits, 1.25s afrer Wes releases his fruit and throws an orange straight down at 28 m/s. Both pieces of fruit hit the ground simultaneously. Calculate the common height from which the fruit were released. Ignore the effects of air resistence.

- Physics -
**drwls**, Saturday, February 2, 2013 at 8:39pm
Start counting time when the apple is thrown. The distance it falls is

D1 = (g/2)t^2 = 4.9 t^2

For the orange, for t>1.25 s,

D2 = 28(t-1.25) + 4.9(t-1.25)^2

Set D1 = D2 and solve for t when they are both at the same distance (ground level).

4.9t^2 = 28(t-1.25) + 4.9(t-1.25)^2

= 28(t-1.25) + 4.9t^2 -12.25 t + 7.656

0 = 15.75 t - 27.34

t = 1.736 s

Use that t in the D1 formula for the building height.

I get 14.8 meters. Check my math.

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