Saturday

December 20, 2014

December 20, 2014

Posted by **Tom** on Saturday, February 2, 2013 at 3:48pm.

∫ (-2-t)(-9-t^2) dt

Now I multiplied both parentheses to get:

∫ (18 + 2t^2 + 9t + t^3) dt

now I integrated and got:

18t + 2t^3/3 + 9t^2/2 + t^4/4 + C

but I'm told this answer is incorrect.

What am I doing wrong?

Thank you

- calculus -
**Damon**, Saturday, February 2, 2013 at 4:10pmI have

(t^2 + 9)(t+2)

is

t^3 + 2 t^2 + 9 t + 18

t^4/4 + (2/3) t^3 + (9/2) t^2 + 18 t + C

I agree with you.

- calculus -
**Tom**, Saturday, February 2, 2013 at 4:12pmokay so there must be a mistake with the system, thanks for clearing that up Damon.

**Answer this Question**

**Related Questions**

Calculus 2 correction - I just wanted to see if my answer if correct the ...

Calculus - Find the general indefinite integral ∫ v(v3+5)2dv

calculus - Find the general indefinite integral ∫cosxsin^4xdx

Calculus. I need help! - Evaluate the indefinite integral (a.)∫√(...

Calculus - Find the integral by substitution ∫ [(16 x3)/(x4 + 5)] dx &#...

Calculus - Suppose that ∫∫_D f(x,y)dA=3 where D is the disk x^2+y^2&...

Integral Help - 1.) ∫ (sin x) / (cos^2 x) dx 2.) ∫ (1) / (1+x^2) dx ...

Calculus - Evaluate the triple integral ∫∫∫_E (x+y)dV where E ...

Calculus - Evaluate the triple integral ∫∫∫_E (x)dV where E is...

Calculus - Evaluate the triple integral ∫∫∫_E (xy)dV where E ...