Posted by Tom on Saturday, February 2, 2013 at 3:48pm.
Using an upper-case "C" for any arbitrary constants, find the general indefinite integral
∫ (-2-t)(-9-t^2) dt
Now I multiplied both parentheses to get:
∫ (18 + 2t^2 + 9t + t^3) dt
now I integrated and got:
18t + 2t^3/3 + 9t^2/2 + t^4/4 + C
but I'm told this answer is incorrect.
What am I doing wrong?
calculus - Damon, Saturday, February 2, 2013 at 4:10pm
(t^2 + 9)(t+2)
t^3 + 2 t^2 + 9 t + 18
t^4/4 + (2/3) t^3 + (9/2) t^2 + 18 t + C
I agree with you.
calculus - Tom, Saturday, February 2, 2013 at 4:12pm
okay so there must be a mistake with the system, thanks for clearing that up Damon.
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