Posted by **Amy** on Saturday, February 2, 2013 at 10:16am.

Q: A reaction rate has a constant of 1.23 x 10-4/s at 28 degrees C and 0.235 at 79 degrees C. Determine the activation barrier for the reaction.

A: My work thus far:

ln(1.23 x 10-4/0.235)=(Ea/8.314)(1/301.15-1/352.15)

-7.551=(Ea/8.314)(0.0048090535)

-7.551=(Ea/8.314)(0.0048090535))

-15,702.808=(Ea/8.314)

Ea= -1,192.24 J/mol

My answer is incorrect, and I would like to know where I went wrong and what the correct answer is.

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