Thursday
August 21, 2014

Homework Help: Temperature Problem

Posted by Amy on Saturday, February 2, 2013 at 10:16am.

Q: A reaction rate has a constant of 1.23 x 10-4/s at 28 degrees C and 0.235 at 79 degrees C. Determine the activation barrier for the reaction.

A: My work thus far:

ln(1.23 x 10-4/0.235)=(Ea/8.314)(1/301.15-1/352.15)
-7.551=(Ea/8.314)(0.0048090535)
-7.551=(Ea/8.314)(0.0048090535))
-15,702.808=(Ea/8.314)
Ea= -1,192.24 J/mol

My answer is incorrect, and I would like to know where I went wrong and what the correct answer is.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Kinetics Problem I - A reaction has a rate constant of 1.2310-4 s at 28 degrees...
How to Plug these values into the Arrhenius Formul - A reaction has a rate ...
Finding the Activation Barrier - Q: A reaction rate has a constant of 1.23 x 10-...
Temperature - Q: A reaction rate has a constant of 1.23 x 10-4/s at 28 degrees C...
science - If a temperature increase from 19.0 degrees C to 36.0 degrees C ...
Arrhenius Reaction - The activation energy of a certain reaction is 32.9 kJ/mol ...
Arrhenius Question - The activation energy of a certain reaction is 32.9 kJ/mol ...
Chemistry - A second order reaction has a rate constant of 8.7x10^-4/(M*s) at 30...
chemistry - I have two questions that I really don't understand. The first one ...
CH102 - If a temperature increase from 18.0 to 34.0 triples the rate constant ...

Search
Members