Posted by Vivan on Saturday, February 2, 2013 at 4:29am.
You are choosing 4 from 30 numbers
= C(30,4) = 30!/(4!26!) = 27405
one of those will be correct
prob(correct #) = 1/27405
2. C(20,4) = ...
3. You don't say which jar we choose from first
but the first jar does not contain a black ball, so the order must be jar1, then jar 2
prob(red,black) = (4/10)(8/13) = 16/65
4. Prob(3 heads out of 5)
= C(5,3) (1/2)^3 (1/2)^2
= 10(1/32) = 5/16
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