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April 18, 2015

April 18, 2015

Posted by **Deborah** on Friday, February 1, 2013 at 8:58pm.

Please help - I do not understand this problem....Thanks

- Algebra-help please -
**Reiny**, Friday, February 1, 2013 at 9:36pmIf I recall the question that Steve already answered for you , it was

|3x-2| = 8 and | x+1| = 0

What he did was to solve the easier of the two, and then asked you to check if these answers satisfied the first.

Why did you not do that?

if |x+1| = 1

then x+1 = 1 or x+1 = -1

x = 0 and x = -2

now test those in the first

if x = 0

LS = | 3(0) - 2|

= |-2| = 2

but RS = 8 , so x = 0 does NOT work in both

if x = -2

LS = |(3(-2) - 2|

= |-8|

= 8 = RS ,

so our solution is x = -2 , since it works in both equations.

- Algebra-help please -
**Deborah**, Friday, February 1, 2013 at 11:32pmNow I understand - I only asked for an explanation...I would have put those into place if I wasn't confused...thanks for the help..didn't mean to bother anyone!

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