Posted by Deborah on Friday, February 1, 2013 at 8:58pm.
If I recall the question that Steve already answered for you , it was
|3x-2| = 8 and | x+1| = 0
What he did was to solve the easier of the two, and then asked you to check if these answers satisfied the first.
Why did you not do that?
if |x+1| = 1
then x+1 = 1 or x+1 = -1
x = 0 and x = -2
now test those in the first
if x = 0
LS = | 3(0) - 2|
= |-2| = 2
but RS = 8 , so x = 0 does NOT work in both
if x = -2
LS = |(3(-2) - 2|
= |-8|
= 8 = RS ,
so our solution is x = -2 , since it works in both equations.
Now I understand - I only asked for an explanation...I would have put those into place if I wasn't confused...thanks for the help..didn't mean to bother anyone!
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