posted by Camaro Lover on .
The normal boiling point of liquid ethanol is 351 K. Assuming that its molar heat of vaporization is constant at 37.5 kJ/mol, the boiling point of C2H5OH when the external pressure is 1.35 atm is K.
Use the Clausius-Clapeyron equation.
You know p = 1 atm when T = 351K. Solve for p2 when T = 1.35 atm.