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October 25, 2014

October 25, 2014

Posted by **Mona** on Friday, February 1, 2013 at 5:48pm.

(there is a drawing of this triangle)

Thanks.

- Geometry-8th gr -
**Reiny**, Friday, February 1, 2013 at 7:40pmI assume the bisector of angle L is LN where N is on KM

In the Post

http://www.jiskha.com/display.cgi?id=1359738761

I proved for you , and Steve called it, the angle bisector theorem

In this case:

KL/KN = LM/MN

11/(x-4) = (2x+1.3)/5.4

2x^2 - 6.7x - 5.2 = 59.4

2x^2 - 6.7x - 64.6 = 0

20x^2 - 67x - 646 = 0

x = (67 ± √56169)/40

= 7.6 or a negative which will not work in 2x+1.3

KN = x-4 = 7.6 - 4 = 3.6

LM = 2x+1.3 = 15.2 + 1.3 = 16.5

check:

LK/KN = 11/3.6 = 55/18

LM/MN = 16.5/5.4 = 55/18

- Geometry-8th gr -
**Mona**, Friday, February 1, 2013 at 9:51pmThanks.

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