Posted by Myke on .
Standing on a bridge, you throw a 3.0 g stone straight upward with speed of 2.5 m/s. How long does it take to return to the original position?
v = v0 + at
0 = 2.5 - 9.8t
t = .255
That's the time to stop rising.
Total time in the air is thus 0.510 sec