Posted by **Graham** on Friday, February 1, 2013 at 3:07pm.

I had a 1.094g of mystery Alum. "AB(SO4)c. dH2O" (I assume that that the Alum is KAl(SO4)2-12H2O but we don't know A B c or d, we do know that mass percent of water is 51.9)

After processing the alum (Ba(NO3)2 and HNO3 through a gooch crucible) we end up with 1.739g of BaSO4.

We know that SO4 is 42.15% of BASO4 thus

SO4 has a mass of .7330 g

assuming we captured all of the SO4 of the original Alum.

so if we subtract .7330g from 1.094g = .361 g

therefor .361g is the the AB and the H2O of the Alum

but if water is 51 of the mass of the Alum. I did something wrong any ideas.

## Answer This Question

## Related Questions

- University Chemistry (first year) - I'm working on a first year chemistry lab ...
- College Chemistry I - A method for recycling scrap aluminum converts it to alum...
- Chemistry Intro - If the solubility of alum is 1g @ 1 degree celcius and 1.7 g ...
- chemistry - Determine the limiting reactant for this reaction if 3.027 grams of ...
- Chemistry - How many moles and how many grams of potassium alum, KAl(SO4)2 · 12...
- Chemistry - Why is my actual percent of sulfate in alum a lot less than my ...
- Chemistry - How would I find the percent of water lost in alum after it has ...
- ap chemistry - The formula for epsom salt is MgSO4 . 7H20 If 1.250 g of the ...
- Chemistry - is KAl(SO4)2 12H2O hygroscopic, deliquescent, or efflorescent?
- Chemistry - Mass of aluminum sample = 0.97g Mass of watch glass = 32.1851g Mass ...

More Related Questions