Posted by Adrianna on .
3x^4=648x
someone help please im so confused. i am trying to find the solution set?

College Algebra 
Reiny,
3x^4  648x = 0
divide by 3
x^4  216x = 0
x(x^3  216)=0
x = 0 or x^3216=0
if you want only real solutions
then from x^3=216
x = 6
however, if you want complex roots at well .....
x^3  216 = (x6)(x^2 + 6x + 36) = 0
x= 6 , we already know that
or
x = (6 ±√108)/2
= (6 ± 6i√3)/2
= 3 ± 3i√3
so x = 0 , 6 , 3±3i√3