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March 29, 2015

March 29, 2015

Posted by **Adrianna** on Friday, February 1, 2013 at 12:26pm.

someone help please im so confused. i am trying to find the solution set?

- College Algebra -
**Reiny**, Friday, February 1, 2013 at 2:53pm3x^4 - 648x = 0

divide by 3

x^4 - 216x = 0

x(x^3 - 216)=0

x = 0 or x^3-216=0

if you want only real solutions

then from x^3=216

x = 6

however, if you want complex roots at well .....

x^3 - 216 = (x-6)(x^2 + 6x + 36) = 0

x= 6 , we already know that

or

x = (-6 ±√-108)/2

= (-6 ± 6i√3)/2

= -3 ± 3i√3

so x = 0 , 6 , -3±3i√3

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