Posted by **Mona** on Friday, February 1, 2013 at 12:11pm.

Given: triangle ABC ~ triangle PQR, m<A = 75 degrees, m<P = (5x + 7y) degrees, m<R = (3x + 4y) degrees, and m<B =( 2x + 9y) degrees. FInd m<R.

Thanks

- Geometry -8th gr -
**Reiny**, Friday, February 1, 2013 at 2:02pm
very similar to the one I did for you yesterday.

draw the two triangles and fill in the information.

5x + 7y = 75 ---- equation #1

In triangle AC

angle C = 180 - 75 - 2x - 9y

= 105 - 2x - 9y

3x+4y = 105 - 2x - 9y

5x + 13y = 105 --- #2

subtract #2 - #1

6y = 30

y = 5

back into #1

5x + 35 = 75

5x = 40

x=8

so if x=8 and y=5

**angle R = 3x+4y = 24+20 = 44°**

check: 5x + 7y should be 75

5(8) + 7(5) = 75 , yeahhh

- Geometry -8th gr -
**Mona**, Friday, February 1, 2013 at 5:24pm
Okay, I get it now:)...thanks.

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