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July 31, 2014

July 31, 2014

Posted by **Vee** on Friday, February 1, 2013 at 7:44am.

zeros -3, 0, and 4

f(1) =10

- algebra -
**Reiny**, Friday, February 1, 2013 at 8:21amif zeros are -3, 0, 4, it could be

f(x) = x(x+3)(x-4)

but (1,10) lies on it , so we have to stretch it to pass through that point without wrecking the zeros

f(x) = ax(x+3)(x-4)

10 = a(4)(-3)

-12a = 10

a = -5/6

f(x) = -(5/6)x(x+3)(x-4)

- algebra -
**Vee**, Friday, February 1, 2013 at 9:55amThank you.

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