PreAlegebra
posted by Bart .
You spin a spinner that is divided into 6 equals parts once and roll the number cube once. Find the probability that the spinner stops on the same number that you roll the number cube?

Wherever the spinner stops, the cube has to match that
so prob = (1)(1/6) = 1/6
or, the long way:
it could be 11 22 33 44 55 66
prob = (1/6)(1/6) + (1/6)(1/6) + ... (1/6)(1/6)
= 1/36 + 1/36+ .. + 1/36 , for 6 terms
= 6(1/36) = 1/6