What volume does 0.25 moles of oxygen gas occupy ar STP?
Assuming O2 is an ideal gas it occupies 0.25 x 22.4L = ?
To determine the volume of a gas at STP (Standard Temperature and Pressure), you can use the ideal gas law, which states:
PV = nRT
Where:
P = Pressure (in units of pressure, usually atm)
V = Volume (in units of volume, usually liters)
n = Number of moles of gas
R = Ideal gas constant (0.0821 L atm / mol K)
T = Temperature (in units of temperature, usually Kelvin)
Since we are given that the gas is at STP, we can use the standard conditions:
P = 1 atm
T = 273.15 K
Now we can rearrange the ideal gas law to solve for volume:
V = (nRT) / P
Substituting the known values:
V = (0.25 mol * 0.0821 L atm / mol K * 273.15 K) / 1 atm
V = 5.65 liters
Therefore, 0.25 moles of oxygen gas at STP occupy a volume of approximately 5.65 liters.