Posted by jamie on Thursday, January 31, 2013 at 6:23pm.
let the 3 consecutive integers be
x-1, x, and x+1
( I wanted to cube x , not x+1 )
x(x-1)(x+1) = x^3 - 22
x^3 - x = x^3 - 22
x = 22
the 3 integers are 21 , 22, and 23
check: product of 3 numbers = 21x22x23 = 10626
cube of 22 = 10648
is the product 22 less than the cube? YES
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