20-(12-x)=38
and
5(3c-c)+3=43
20-(12-x)=38
8 - x = 38
x = -30
I'll be glad to check your answer for the second problem.
5(3c-c)+3=43
(15c-5c)+3=48
-3 -3
---------------
15c-5c= 45
+5 +5
---------------
15c = 45
c=3
5(3c-c)+3=43
15c - 5c + 3 = 43
10c = 43 - 3
10c = 40
c = 4
To solve these equations, we'll follow a step-by-step approach for each equation:
1. Solve the first equation: 20 - (12 - x) = 38
To simplify the equation, let's remove the parentheses first:
20 - 12 + x = 38
Next, combine like terms:
8 + x = 38
Now, isolate the variable x by subtracting 8 from both sides:
x = 38 - 8
x = 30
Therefore, the solution to the first equation is x = 30.
2. Solve the second equation: 5(3c - c) + 3 = 43
Start by simplifying within the parentheses:
5(2c) + 3 = 43
Next, distribute the 5 to each term within the parentheses:
10c + 3 = 43
Now, isolate the variable c by subtracting 3 from both sides:
10c = 43 - 3
10c = 40
Finally, divide both sides by 10 to solve for c:
c = 40 / 10
c = 4
Therefore, the solution to the second equation is c = 4.