posted by Vee on .
Please help me.
Find the equation of the line satisfying the indicated properties. Express your answer in
Passing through point (-2, 4) and perpendicular to the line containing points (3, -1) and (5, -1).
slope of line through (3,-1) and (5,-1) = 0
which is a horizontal line
so our new line is a vertical line, thus the slope is undefined
it must pass through (-2,4) and its equation would simply be
x = -2
(A vertical line cannot be expressed in the y = mx + b form, and you should not have been instructed to do so)
Thank you so much.