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Please help me.

Find the equation of the line satisfying the indicated properties. Express your answer in
slope-intercept form.

Passing through point (-2, 4) and perpendicular to the line containing points (3, -1) and (5, -1).

  • algebra -

    slope of line through (3,-1) and (5,-1) = 0
    which is a horizontal line
    so our new line is a vertical line, thus the slope is undefined
    it must pass through (-2,4) and its equation would simply be
    x = -2

    (A vertical line cannot be expressed in the y = mx + b form, and you should not have been instructed to do so)

  • algebra -

    Thank you so much.

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