Posted by **Vee** on Thursday, January 31, 2013 at 5:44pm.

Please help me.

Find the equation of the line satisfying the indicated properties. Express your answer in

slope-intercept form.

Passing through point (-2, 4) and perpendicular to the line containing points (3, -1) and (5, -1).

- algebra -
**Reiny**, Thursday, January 31, 2013 at 7:56pm
slope of line through (3,-1) and (5,-1) = 0

which is a horizontal line

so our new line is a vertical line, thus the slope is undefined

it must pass through (-2,4) and its equation would simply be

x = -2

(A vertical line cannot be expressed in the y = mx + b form, and you should not have been instructed to do so)

- algebra -
**Vee**, Thursday, January 31, 2013 at 8:29pm
Thank you so much.

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