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July 25, 2014

July 25, 2014

Posted by **Zico johnny** on Thursday, January 31, 2013 at 5:14pm.

- Mathematics -
**Ravin**, Thursday, January 31, 2013 at 5:22pm2x+6 < 5(x-3) distribute 5 into x-3

2x+6 < 5x-15 move all x to one side

6 < 5x-15-2x simplify

6 < 3x-15 move 15 to other side

6+15 < 3x simplify

21 < 3x get x alone by dividing 3 on both sides

21/3 < 3x/3 simplify

7 < x and thats how you solve it.

- Mathematics -
**PsyDAG**, Thursday, January 31, 2013 at 5:23pm2x + 6 < 5x -15

Add 15 and subtract 2x from both sides.

21 < 3x

Divide both sides by 3.

7 < x

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