Posted by Erica on Thursday, January 31, 2013 at 4:28pm.
y(t)=sqrt(2 ln|t-2|+C)-1
If y is to be zero when t = 0 then
1 = sqrt (2 ln 2 +C)
C = 1 -2 ln 2 = -.386
y = sqrt (2 ln|t-2| -.386) - 1
You can not take ln of zero or a negative number so t may not be equal to 2
Try some solutions around t = t to see what happens to y
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