Posted by Patrick on Thursday, January 31, 2013 at 3:45pm.
the relative molecular mass of lead 2 trioxonitrate V is (pb=180,N=14, O=16).
Since the dissociation constant is equal to the inverse of the association constant, it is possible to figure this out. It would be the one with the lowest dissociation contant or the one with the highest association constant. Ligand A has a lower dissociation constant then B, so B is eliminated. Since 30% occupancy requires the ligand must greater than 3 times the number of it's dissociation constant, and the units for the dissociation constant are given in M. After converting everything to M, the equations for ligand C and D will be the following:
1x10^-6=3(Kd)
10x10^-9=8(Kd)
Solving for Kd,
Ligand C's Kd=3.3 x10^-7
Ligand D's Kd=1.2 x10^-9
The answer is Ligand A
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