Posted by **xavier** on Thursday, January 31, 2013 at 8:39am.

Find the equation of the circle, with radius 1, tangent to the line 3x+4y=5 and having its center on the line x+2y=0

- Analytic Geometry -
**Reiny**, Thursday, January 31, 2013 at 9:30am
let the centre be (a,b)

but it must lie on x+2y=0, so a+2b=0

a = -2b

we can call our centre (-2b, b)

its distance to 3x + 4y - 5 must be 1

| 3(-2b) + 4b - 5 }/√(3^2+4^2) = 1

case 1:

(-6b+4b-5)/√25 = 1

-2b - 5 = 5

b = -5

a= 10 ----> equation: (x-10)^2 + (y+5)^2 = 1

case 2:

6b - 4b + 5 = 5

2b = 0

b=0

a=0 ----------> x^2 + y^2= 1

make a sketch to see if both are possible

What do you think?

## Answer this Question

## Related Questions

- Analytic Geometry - Find the equation of the circle with radius sqrt2 tangent to...
- calc - standard equation of circle concentric with X^2+Y^2-2X-8Y+1=0 and tangent...
- Analytic Geometry - What is the equation of the circle touching the lines x-3y-...
- Analytic Geometry - What is the equation of the circle touching the lines x-3y-...
- Analytic Geometry - What is the equation of the circle touching the lines x-3y-...
- Analytic Geometry - Find the equation of a circle passing through (3,7) and ...
- Analytic Geometry - Find the equation of a circle passing through and tangent to...
- Analytic Geometry - Find the equation of a circle passing through (3,7) and ...
- Analytic Geometry - Find the equation of a circle passing through (3,7) and ...
- Math (geometry) - Line l is tangent to circle O at point P(3,4) where the center...