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Posted by on Thursday, January 31, 2013 at 2:41am.

A researcher studying the nutritional value of a new candy places a 4.30-gram sample of the candy inside a bomb calorimeter and combusts it in excess oxygen. The observed temperature increase is 2.77 °C. If the heat capacity of the calorimeter is 28.90 kJ·K–1, how many nutritional Calories are there per gram of the candy?

Please help, I don't know how to start!

  • Chemistry - , Thursday, January 31, 2013 at 1:27pm

    q = Ccal x delta T
    (Ccal is heat capacity of the calorimeter 28.90 kJ/K and delta T = 2.77 C).
    Solve for q = heat produced by 4.30 g of the candy in kJ.
    Convert that J (multiply by 1000).
    Convert that to calories (divide by 4.184).
    Convert that to nutritional calories (divide by 1000) which gives you calories for the 4.30 g piece of candy.
    Divide by 4.30 to convert to nutritional calories/grams candy.

  • Chemistry - , Saturday, February 2, 2013 at 12:21am

    Thank you so much!

  • Chemistry - , Tuesday, March 26, 2013 at 3:04pm

    Is K kalvin? If so, why isn't celcius converted?

  • Chemistry - , Tuesday, March 26, 2013 at 3:04pm

    Kelvin*

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