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March 4, 2015

March 4, 2015

Posted by **Sania** on Thursday, January 31, 2013 at 2:14am.

- Math -
**Reiny**, Thursday, January 31, 2013 at 9:14amI am NOT even, and I am a multiple of 5 ---> must end in 5

must look like AB5

must be between 200 and 300 ,so A = 2

must look like 2B5

to be divisible by 9 , the sum of the digits must be a multiple of 9

so 2+B + 5 = a multiple of 9

B = 2

your number is 225

check for all the required properties.

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