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February 1, 2015

February 1, 2015

Posted by **Barb** on Thursday, January 31, 2013 at 2:05am.

by using the identity

(x - y/2)^2 = (x + y/2)^2 - xy

- Math -- Please Help -
**Reiny**, Thursday, January 31, 2013 at 9:08ammmmh, can't quite see how that helps

I would just do:

y = 1/x

sub into 2nd

x + 1/x = a

x^2 + 1 = ax

x^2 - ax + 1 = 0

x = (a ± √(a^2 - 4) )/2

y = 2/(a ± √(a^2 - 4) )

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