Solve the system xy = 1, x + y =a
by using the identity
(x - y/2)^2 = (x + y/2)^2 - xy
mmmh, can't quite see how that helps
I would just do:
y = 1/x
sub into 2nd
x + 1/x = a
x^2 + 1 = ax
x^2 - ax + 1 = 0
x = (a ± √(a^2 - 4) )/2
y = 2/(a ± √(a^2 - 4) )