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Math -- Please Help

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Solve the system xy = 1, x + y =a
by using the identity

(x - y/2)^2 = (x + y/2)^2 - xy

  • Math -- Please Help - ,

    mmmh, can't quite see how that helps

    I would just do:
    y = 1/x
    sub into 2nd
    x + 1/x = a
    x^2 + 1 = ax
    x^2 - ax + 1 = 0

    x = (a ± √(a^2 - 4) )/2
    y = 2/(a ± √(a^2 - 4) )

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