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September 16, 2014

September 16, 2014

Posted by **Rachel** on Thursday, January 31, 2013 at 1:07am.

s(t) = -20t^2 +67t +42 feet at time t seconds after it is thrown.

a) From what height was the object thrown?

b) With what velocity was the object thrown?

c) What is the acceleration due to gravity on this planet?

- calculus 2 -
**Reiny**, Thursday, January 31, 2013 at 8:37ama) sub in t=0 into s(t)

b) find the derivative to get velocity

c) find the derivative of velocity to get acceleration.

You will get a constant.

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