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Calculus

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Let f(x)= 6x+(4/x^2). then the equation of the tangent line to the graph of f(x) at the point (2,13) is given by y=mx+b.

What is m and what is b?

  • Calculus - ,

    or f(x) = 6x + 4x^-2
    f ' (x) = 6 - 8x^-3 or 6 - 8/x^3

    at (2,13) , slope = 6 - 8/2^3 = 6-1 = 5

    so y = 5x + b
    sub in your given point
    13 = 5(2) + b
    b = 3

    in y = 5x + 3 , m=5 and b=3

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