Thursday

December 18, 2014

December 18, 2014

Posted by **Scott** on Wednesday, January 30, 2013 at 10:29pm.

(2.5 cm)sin[(3.0 m-1)x - (27 s-1 )t]

and

(2.5 cm)sin[(3.0 m-1)x + (27 s-1)t]

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