Monday
March 27, 2017

Post a New Question

Posted by on .

If the freezing point of pure toluene is -95.15 oC and its freezing point depression constant is -8.38 oC/molal, what is the freezing point of a solution made by dissolving 39.338g of anthracene (C14H10) in 150.0mL of toluene? (Density of toluene = 0.8669g/mL)

  • Chemistry - ,

    mol anthracene = grams/molar mass
    grams toluene = volume x density
    molality = mol anthracene/kg toluene.
    delta T = Kf*m. Solve for delta T.
    Subtract from zero to find new freezing point.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question