tom has a collection of 50 cds and nita has a collection of 38 cds. Each month tom adds two cds and nita adds four how many months will it take until they have the same amount?

Damon answered a very similar question a couple of days back

http://www.jiskha.com/display.cgi?id=1327699984

In 6 months

It is 3 months . I don't really remember how to show my work but I remember it was 3 months .

To solve this problem, we need to find the number of months it takes for Tom and Nita to have the same number of CDs.

Initially, Tom has 50 CDs and Nita has 38 CDs.
Every month, Tom adds 2 CDs to his collection, while Nita adds 4 CDs to her collection.

Let's assume it takes 'x' months for them to have the same number of CDs.

After x months:
- Tom will have added 2*x CDs to his initial collection of 50 CDs, making it 50 + 2*x CDs.
- Nita will have added 4*x CDs to her initial collection of 38 CDs, making it 38 + 4*x CDs.

To find the point when they have the same number of CDs, we can set up an equation:

50 + 2*x = 38 + 4*x

Now, let's solve for x.

Subtracting 38 from both sides of the equation:
50 + 2*x - 38 = 38 + 4*x - 38
12 + 2*x = 4*x

Subtracting 2*x from both sides of the equation:
12 + 2*x - 2*x = 4*x - 2*x
12 = 2*x

Dividing both sides by 2:
12/2 = 2*x/2
6 = x

Therefore, it will take 6 months for Tom and Nita to have the same number of CDs.