Monday

March 2, 2015

March 2, 2015

Posted by **Amy** on Wednesday, January 30, 2013 at 7:56pm.

Given that the initial rate constant is 0.0160 s-1 at an initial temperature of 25 degrees C , what would the rate constant be at a temperature of 130 degrees C for the same reaction described in Part A?

------------------

I managed to be given the formula: ln(k2/0.0160) = (32900/0.08206)(1/298/15 - 1/403.15) but when I answered it, I got the wrong answer.

- Arrhenius Question -
**DrBob222**, Wednesday, January 30, 2013 at 9:11pmNote that there are two questions here. The answer I gave you yesterday was for the second one. Did you report that answer for the first or the second one? Next, you simply copied what I gave you. Show your work, including the answer, and I will try to find the error.

**Answer this Question**

**Related Questions**

Arrhenius Reaction - The activation energy of a certain reaction is 32.9 kJ/mol ...

Temperature and Rate - Q: The activation energy of a certain reaction is 32.9 ...

Corrected Temperature Problem - Q: The activation energy of a certain reaction ...

Chemistry - The activation energy of a certain reaction is 34.9kJ/mol . At 23...

Rate Constant - My Work is Incorrect - Hi! I am stuck with this question and I ...

chemistry - I have two questions that I really don't understand. The first one ...

AP Biology - The respiration of plants is a biochemical reaction and should have...

Chemistry 104 - A reaction rate doubles when the temperature increases from 0 ...

Chemistry 104 - A reaction rate doubles when the temperature increases from 0 ...

Chemistry, Arrhenius law - The rate constant of a first order reaction is 4....