Posted by **Amy** on Wednesday, January 30, 2013 at 7:56pm.

The activation energy of a certain reaction is 32.9 kJ/mol At 25 degrees C the rate constant is 0.0160 units s-1 units. At what temperature in degrees Celsius would this reaction go twice as fast?

Given that the initial rate constant is 0.0160 s-1 at an initial temperature of 25 degrees C , what would the rate constant be at a temperature of 130 degrees C for the same reaction described in Part A?

------------------

I managed to be given the formula: ln(k2/0.0160) = (32900/0.08206)(1/298/15 - 1/403.15) but when I answered it, I got the wrong answer.

- Arrhenius Question -
**DrBob222**, Wednesday, January 30, 2013 at 9:11pm
Note that there are two questions here. The answer I gave you yesterday was for the second one. Did you report that answer for the first or the second one? Next, you simply copied what I gave you. Show your work, including the answer, and I will try to find the error.

## Answer This Question

## Related Questions

- Arrhenius Reaction - The activation energy of a certain reaction is 32.9 kJ/mol ...
- Temperature and Rate - Q: The activation energy of a certain reaction is 32.9 ...
- Corrected Temperature Problem - Q: The activation energy of a certain reaction ...
- Chemistry - The activation energy of a certain reaction is 34.9kJ/mol . At 23...
- chemistry - 1) The activation energy of a certain reaction is 35.3 kJ/mol. At ...
- chemistry - I have two questions that I really don't understand. The first one ...
- Rate Constant - My Work is Incorrect - Hi! I am stuck with this question and I ...
- chem - The activation energy of a certain reaction is 30.3 kJ/mol. At 20 C, the ...
- AP Biology - The respiration of plants is a biochemical reaction and should have...
- Chemistry 104 - A reaction rate doubles when the temperature increases from 0 ...

More Related Questions