Physics
posted by Tiffany on .
How much energy is required to change a 58 g ice cube from ice at −1◦C to steam at 101◦C? The specific heat of ice is 2090 J/kg ·◦ C and of water 4186 J/kg ·◦ C. The latent heat of fusion of water is 3.33 × 105 J/kg, its latent heat of vaporization is 2.26 × 106 J/kg, and the specific heat of steam is 2010 J/kg ·◦ C.
Answer in units of MJ

c₁=2090 J/kg ,c₂ = 4186 J/kg •◦ C,
c₃ =2010 J/kg •◦ C.
λ = 3.33•10^5 J/kg, r = 2.26• 10^6 J/kg.
m=0.058 kg
Q= c₁m(1)+ λm +c₂m(100) +rm + c₃m(1) = …(J)
1MJ = 10⁶J