Posted by **Fall** on Wednesday, January 30, 2013 at 4:37pm.

At a certain instant, each edge of a cube is 5 inches long and the volume is increasing at the rate of 2 cubic inches per minute. How fast is the surface area of the cube increasing?

- Calculus -
**Steve**, Wednesday, January 30, 2013 at 5:26pm
a = 6s^2

da/dt = 12s ds/dt

da/dt = 12*5*2 = 120 in^2/min

- Calculus -
**Reiny**, Wednesday, January 30, 2013 at 5:50pm
V = s^3

dV/dt = 3v^2 ds/dt

when s = 5, dV/dt = 2

2 = 3(25) ds/dt

ds/dt = 2/75

A = 6s^2

dA/dt = 12s ds/st

= 12(5) (2/75) = 8/5 inches^2 / min

## Answer this Question

## Related Questions

- Calculus - The edge of a cube is increasing at a rate of 2 inches per minute. ...
- calculus - at a certain instant the base of a triangle is 5 inches and is ...
- math - The radius r of a sphere is increasing at the uniform rate of 0.3 inches ...
- AB Calculus - I figured out that part "A" is -3/8, but i can't figure out part 2...
- calculus - a spherical snowball with diameter 4 inches is removed from the ...
- calculus help please - At the instant when the radius of a cone is 3 inches, the...
- calculus - At the instant when the radius of a cone is 3 inches, the volume of ...
- AP calculus AB - At the instant when the radius of a cone is 3 inches, the ...
- AP CALC. AB - Please help me with this problem and please walk me through each ...
- Math - The surface area of a cube is 384 square inches. What is the volume of ...