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December 19, 2014

December 19, 2014

Posted by **Fall** on Wednesday, January 30, 2013 at 4:36pm.

- Calculus -
**Steve**, Wednesday, January 30, 2013 at 5:25pmv = x(16-2x)^2 = 2x(8-x)^2

dv/dx = 4(3x-8)(x-8)

x=8 is obviously a minimum (v=0), so

max volume is at x = 8/3

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