Friday

November 21, 2014

November 21, 2014

Posted by **tyson** on Wednesday, January 30, 2013 at 12:54pm.

(x^2/3600)+(y^2/1600)= 1

The cross sections perpendicular to the ground and parallel to the y-axis are squares. Find the total volume of the pool.

- calculus -
**Steve**, Wednesday, January 30, 2013 at 3:10pmIntegrating along x, the area of each cross-section is (2y)^2 = 4y^2.

The equation of the ellipse means

4y^2 = 6400 - 6400x^2/3600 = 6400 - 8/9 x^2

v = ∫[-60,60] 6400 - 8/9 x^2 dx

let 'er rip.

**Answer this Question**

**Related Questions**

Calculus - a swimming pool has the shape of the ellipse given by (x^2)/3600 + (y...

calculus - #3 A solid has a base in the form of the ellipse: x^2/25 + y^2/16 = 1...

calculus - The region A is bounded by the curve y=x^2-5x+6 and the line y = -x...

Calculus - R is the region in the plane bounded below by the curve y=x^2 and ...

Calculus - R is the region in the plane bounded below by the curve y=x^2 and ...

Calculus - R is the region in the plane bounded below by the curve y=x^2 and ...

College Calculus - Find the volume of the solid with given base and cross ...

Calculus - Calculate the volume of the ramp in Figure 17 in three ways by ...

calc - What is the volume of the solid with given base and cross sections? The ...

Calculus - Let R be the region bounded by y=6sin((pi/2)x), y=6(x-2)^2, y=3x+3 ...