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December 21, 2014

December 21, 2014

Posted by **tyson** on Wednesday, January 30, 2013 at 12:54pm.

(x^2/3600)+(y^2/1600)= 1

The cross sections perpendicular to the ground and parallel to the y-axis are squares. Find the total volume of the pool.

- calculus -
**Steve**, Wednesday, January 30, 2013 at 3:10pmIntegrating along x, the area of each cross-section is (2y)^2 = 4y^2.

The equation of the ellipse means

4y^2 = 6400 - 6400x^2/3600 = 6400 - 8/9 x^2

v = ∫[-60,60] 6400 - 8/9 x^2 dx

let 'er rip.

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