Posted by **tyson** on Wednesday, January 30, 2013 at 12:51pm.

The base of a certain solid is the triangle with vertices at (-14,7),(7,7) and the origin. Cross-sections perpendicular to the y-axis are squares. What is the volume of this solid?

- Calculus -
**Steve**, Wednesday, January 30, 2013 at 3:05pm
Integrating along y, the area of each cross-section is (2x)^2, so

v = ∫[0,7] (2x)^2 dy

Now, x = (7-y), so

v = ∫[0,7] (2(7-y))^2 dy

= 4* 1/3 (y-7)^3 [0,7]

= 1372/3

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