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February 28, 2015

February 28, 2015

Posted by **tyson** on Wednesday, January 30, 2013 at 12:51pm.

- Calculus -
**Steve**, Wednesday, January 30, 2013 at 3:05pmIntegrating along y, the area of each cross-section is (2x)^2, so

v = ∫[0,7] (2x)^2 dy

Now, x = (7-y), so

v = ∫[0,7] (2(7-y))^2 dy

= 4* 1/3 (y-7)^3 [0,7]

= 1372/3

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