How much heat must be removed from a 200 g block of copper to lower its temperature from 302 oF to 68

oF?
Specific heat of copper: c = 0.092 kcal/(kg K)
a. 2.4 kcal
b. 2400 kcal
c. 18.4 kcal
d. 12 kcal
e. 26 kcal

Well, let's do some temperature acrobatics! To find the amount of heat that must be removed, we can use the formula:

Q = mcΔT

Where:
Q = amount of heat
m = mass of the copper block
c = specific heat of copper
ΔT = change in temperature

Given:
m = 200 g
c = 0.092 kcal/(kg K)
ΔT = (302 - 68) oF = 234 oF

Now, let's convert the mass to kg and the change in temperature to Kelvin:

m = 200 g = 0.2 kg
ΔT = 234 oF = 234 K

Plugging these values into the formula:

Q = (0.2 kg) * (0.092 kcal/(kg K)) * (234 K)
Q ≈ 4.314 kcal

Looks like none of the answer choices match exactly. But hey, let's be funny and round it off!

So, the closest answer would be 4.3 kcal, but since it's not provided, I'll have to say none of the above. Just like a circus clown, I like to keep things unpredictable!

To calculate the amount of heat that needs to be removed, we can use the formula:

Q = mcΔT

Where:
Q is the heat energy
m is the mass of the copper block
c is the specific heat of copper
ΔT is the change in temperature (final temperature - initial temperature)

Let's plug in the given values:

m = 200 g = 0.2 kg
c = 0.092 kcal/(kg K)
ΔT = (68 oF - 302 oF) = -234 oF

Now, convert the temperature change from Fahrenheit to Kelvin:

ΔT = (-234 oF) × (5/9) = -130 K

Substitute the values into the formula:

Q = (0.2 kg) × (0.092 kcal/(kg K)) × (-130 K)
Q = -2.408 kcal

Since we are looking for the amount of heat that needs to be removed, the answer should be in positive value:

Q = 2.408 kcal

Therefore, the correct answer is option a. 2.4 kcal.

To calculate the amount of heat that needs to be removed from a substance to lower its temperature, you can use the formula:

Q = mcΔT

where:
Q is the heat energy transferred,
m is the mass of the substance,
c is the specific heat capacity of the substance, and
ΔT is the change in temperature.

Given:
m = 200 g (or 0.2 kg)
ΔT = (68 - 302) °F = -234 °F = -129.8 °C
c = 0.092 kcal/(kg K)

First, convert the change in temperature from Celsius to Kelvin:
ΔT = -129.8 + 273.15 = 143.35 K

Now, plug in the values into the formula:
Q = (0.2 kg) * (0.092 kcal/(kg K)) * (143.35 K)
Q ≈ 2.66 kcal

The amount of heat that needs to be removed from the block of copper is approximately 2.66 kcal. However, none of the answer choices provided matches this value.