Posted by Merlina_Lyn on Wednesday, January 30, 2013 at 10:18am.
calculate the 0.4M molarity of ammonia
From data given, how to prepare 200ml of 0.4M ammonia solution 25%. From previous study, i found that the calculation is M1V1=M2V2
From formula, Initial concentration (M1)is 910000mg/L, vOlume of beaker (V2)=200ml, but the required concentration (M2)? from previous study state M2=6815.2 mg/L <--------how to get this?? and V1 will be 1.498ml..do help me please
- Chemistry - Devron, Wednesday, January 30, 2013 at 1:28pm
I would help, but I am not all that positive about the information provided. This is what I believe you are saying: You want to make 200mL of a 0.4M solution using 25% ammonia by m/v. However, I do not know if the value for M2 and V1 are values that you calculated or are values that are provided for you as the answer, but if they are the answers that you calculated, I do not believe they are correct.
25% of ammonia by m/v= 25g/mL
25g/17.03 g of NH3 *mole-1=1.47 moles of NH3
Therefore, the 25% of ammonia by m/v =1.47 moles/mL
In order to use the above equation, which is correct, I need to make sure that my units are the same. It is easier to convert mL to L, so I will do that for the initial solution and for the volume of 0.4M solution needed.
1.47moles/mL*(1mL/10^-3 L) =1470 moles/L=1470M
I know that the molarity that I want is 0.4M, and I know the volume needed, is 0.200L. Since I already have converted my 25% solution to molarity, all I need to do is solve for the volume of the 25% solution that I need to dilute to make a 0.4M solution using the equation that you provided.
Solving for V1,
V1=[(0.4M)(0.200L)]/(1470M)=5.45 x 10^-5 L
5.45 x 10^-5 L*(10^3 mL/1L)= 5.45 x 10^-2 L
I hope this helps.
- Chemistry - Devron, Wednesday, January 30, 2013 at 5:24pm
Last line should say 5.45 x 10^-2 mL
Answer This Question
More Related Questions
- chemistry - A 1M solution (200ml) of NH3 (Kb of ammonia=1.8*10-5) is added to ...
- Chemistry - Aqueous ammonia is typically sold by chemical supply houses as the ...
- Chemistry - 1. Calculate the acetylsalicylic acid concentration (in mg/mL) of ...
- Chemistry - Ammonia has the formula NH3. Household ammonia is a dilute aqueous ...
- chemistry - My problem is calculate the molarity of HCl and NaOH. (molarity of ...
- chemistry - I am doing a home lab experiment about acid-base neutralization. I ...
- Chemistry - A sample of ammonia gas was allowed to come to equilibrium at 400 K...
- Brad - My problem is calculate the molarity of HCl and NaOH (molarity of acid)x(...
- Chemistry - A 51.46 mL sample of an ammonia solution is analyzed by titration ...
- chemistry - . Given the following stocks 4M NaCl, 3M NaOH, 5M HCl (a) Prepare ...