Having trouble with a statistics question. If you have 2 groups..group A and group B and Group A's times in seconds are 3, 7, 8, 25, 132, and 132 and Group B's times are 2,3, 5,7,23,33,40, 44, 46, 51, 70, 125, and 134...which group overall found the hidden candy the fastest and why? Thanks

if 3/5 of a group of children were girls, and there were 24 girls, how many children were in the group?

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To determine which group overall found the hidden candy the fastest, we need to compare the times of Group A and Group B.

Step 1: Find the average time for each group.
To find the average time for each group, sum up all the times and divide by the number of observations.

For Group A:
3 + 7 + 8 + 25 + 132 + 132 = 307
Average time for Group A = 307 / 6 = 51.17 seconds (rounded to two decimal places)

For Group B:
2 + 3 + 5 + 7 + 23 + 33 + 40 + 44 + 46 + 51 + 70 + 125 + 134 = 633
Average time for Group B = 633 / 13 = 48.69 seconds (rounded to two decimal places)

Step 2: Compare the average times.
Comparing the average times, we can see that Group B had a slightly faster average time (48.69 seconds) compared to Group A's average time (51.17 seconds). Therefore, Group B found the hidden candy overall faster than Group A.

Step 3: Explanation
The average time provides a measure of central tendency for each group. In this case, a lower average time indicates that, on average, the individuals in that group took less time to find the hidden candy. Since Group B's average time is lower than Group A's, we can conclude that, on average, the individuals in Group B found the hidden candy faster.