Posted by luke on Wednesday, January 30, 2013 at 5:26am.
The equation shows that 1 mole of K₂SO₄ is needed to react with mole of Ba ions.
Just eyeballing the numbers that you provided, the K₂SO₄ that you provided is in excess compared to Ba ions in the reaction. Therefore, the amount of K₂SO₄ will be sufficient to precipitate Ba.
If you need to know how to do this calculation wise, Molarity*volume in L=moles
convert mL to L by multiplying the volume by 10^-3.
moles of K₂SO₄>Ba (NO₃)₂, Ba will precipitate.
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