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Posted by on Wednesday, January 30, 2013 at 12:46am.

find the equation of the line tangent to the graph y=3e^x at x=1

  • calculus - , Wednesday, January 30, 2013 at 11:20am

    you have a point (1,3e)
    and a slope y'(1) = 3e

    so, the line is

    y-3e = 3e(x-1)

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