Posted by Amy on .
The activation energy of a certain reaction is 32.9 kJ/mol At 25 degrees C the rate constant is 0.0160 units s1 units. At what temperature in degrees Celsius would this reaction go twice as fast?
Given that the initial rate constant is 0.0160 s1 at an initial temperature of 25 degrees C , what would the rate constant be at a temperature of 130 degrees C for the same reaction described in Part A?

Arrhenius Reaction 
DrBob222,
What's your trouble with this?
b.
ln(k2/k1) = (Ea/R)(1/T1  1/T2)
ln(k2/0.0160) = (32900/0.08206)(1/298/15  1/403.15)
Solve for k2. 
Arrhenius Reaction 
Krystal Nickelback,
Roses are red,
Violets are blue,
I'm terrible at Chemistry
And apparently, you are too <3