Posted by Anonymous on .
find the volume of the solid generated by revolving around the xaxis: y=e^(x8), y=0, x=0, x=10
So I know you can use the washer method, but the shell method can also be used and it should be better. The issue is I'm not certain how to actually do it. Any help is appreciated!

calc 
Steve,
washers:
v = ∫[0,10] πr^2 dx
where r = y = e^(x8)
v = π∫[0,10] (e^(x8))^2 dx
= π∫[0,10] e^(2x16) dx
= π/2 e^(2x16) [0,10]
= π/2 (e^4  1/e^16)
shells:
y = e^(x8), so x = 8+lny
v = ∫[e^8,e^2] 2πrh dy
where r = y and h = 10x = 2lny
v = 2π∫[e^8,e^2] y(2lny) dy
= π/2 (y^2(52lny)) [e^8,e^2]
= π/2 (e^4  21/e^16)
Hmmm. better doublecheck my math. Anyway, that's the method.