How many grams of N2 are produced when 15.0 moles of NH3 react with excess NO
4NH3 + 5O2 ---> 4NO + 6H2O
The moles of NH3= the moles of NO
15 moles of NO*(30.01g of NO/mol)= g of NO
To determine the number of grams of N2 produced when 15.0 moles of NH3 react with excess NO, we need to use the balanced chemical equation and the molar ratios.
The balanced chemical equation for the reaction between NH3 and NO is as follows:
4 NH3 + 6 NO -> 5 N2 + 6 H2O
From the equation, we can see that for every 4 moles of NH3, 5 moles of N2 are produced.
Step 1: Calculate the moles of N2 produced using the mole ratio:
Moles of N2 = (15.0 moles of NH3) x (5 moles of N2 / 4 moles of NH3)
Moles of N2 = 18.75 moles of N2
Step 2: Convert moles of N2 to grams using the molar mass:
Molar mass of N2 = 28.02 g/mol
Mass of N2 = (18.75 moles of N2) x (28.02 g/mol)
Mass of N2 = 524.57 grams of N2
Therefore, when 15.0 moles of NH3 react with excess NO, 524.57 grams of N2 are produced.
To determine the number of grams of N2 produced, we need to use the balanced chemical equation for the reaction between NH3 and NO. The balanced equation is as follows:
4 NH3 + 6 NO --> 5 N2 + 6 H2O
From the balanced equation, we can see that 4 moles of NH3 react with 6 moles of NO to produce 5 moles of N2.
To find the number of moles of N2 produced, we can use the given information about NH3:
15.0 moles of NH3
Using the mole ratio from the balanced equation, we can set up the following conversion:
15.0 moles NH3 x (5 moles N2 / 4 moles NH3) = moles of N2
Now, we can calculate the moles of N2 produced:
15.0 moles NH3 x (5 moles N2 / 4 moles NH3) = 18.75 moles N2
Finally, we need to convert the moles of N2 into grams. To do this, we need to use the molar mass of N2, which is approximately 28.02 g/mol.
To convert moles to grams, we multiply by the molar mass:
18.75 moles N2 x 28.02 g/mol = 524.625 grams N2
Therefore, approximately 524.63 grams of N2 are produced when 15.0 moles of NH3 react with excess NO.