Posted by Lea on Tuesday, January 29, 2013 at 10:34pm.
let the centre be (a,b)
but (a,b) lies on y = 4x
so b = 4a
and we can call our centre (a, 4a)
so the equation of our circle is
(x-a)^2 + (y-4a)^2 = 2
we know the distance from (a,4a) to
x+y-3 = 0 is √2
|a + 4a - 3|/√(1+1) = √2
5a - 3 = 2
5a = 5
a = 1
so the circle equation is
(x-1)^2 + (y-4)^2 = 2
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