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pre-calculus

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(2^(4+pi))/ 2^(1+pi)

  • pre-calculus -

    remember, when dividing powers with the same base ...
    we keep the base and subtract the exponents

    4+π - (1+π)
    = 4+π-1-π = 3

    so
    (2^(4+pi))/ 2^(1+pi)
    = 2^3
    = 8

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